5/x-5-10/x^2=0

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Solution for 5/x-5-10/x^2=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x-(10/(x^2))-5 = 0

5/x-10*x^-2-5 = 0

5*x^-1-10*x^-2-5 = 0

t_1 = x^-1

5*t_1^1-10*t_1^2-5 = 0

5*t_1-10*t_1^2-5 = 0

DELTA = 5^2-(-10*(-5)*4)

DELTA = -175

DELTA < 0

x belongs to the empty set

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